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Math Exam 2
Algebraic equations: solutions or classification 1a. Solve 4(x+2)−6(1−x)=624(x+2) – 6(1-x) = 62 4x+8−6+6x=624x + 8 – 6 + 6x = 62 10x+2=6210x + 2 = 62 10x=60⇒x=610x = 60 \Rightarrow x = 6 1b. Solve 5x+3−2x=−4+10x+7−7x5x + 3 – 2x = -4 + 10x + 7 – 7x LHS: 3x+3,RHS: 3x+3\text{LHS: } 3x + 3,\quad \text{RHS: }…
Math Exam 1
Algebraic expressions and evaluations 1. Writing or solving algebraic problems
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